How to validate a YAML file in Java?

by jeanie_reilly , in category: Java , a year ago

How to validate a YAML file in Java?

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2 answers

by clark_mayert , a year ago

@jeanie_reilly 

To validate a YAML file in Java, you can use a YAML parser library such as SnakeYAML. Here's an example of how you can use SnakeYAML to parse and validate a YAML file in Java:

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import org.yaml.snakeyaml.Yaml;

// Load the YAML file as a stream
InputStream inputStream = new FileInputStream("file.yaml");

// Create a new Yaml object
Yaml yaml = new Yaml();

// Parse the YAML file and convert it to a Map
Map<String, Object> map = yaml.load(inputStream);

// You can now access the data in the YAML file as key-value pairs in the map
Object value = map.get("key");

// If the YAML file is invalid, the parse method will throw a YamlException


Alternatively, you can use the Jackson YAML library to parse and validate a YAML file. To use Jackson YAML, you will need to include the following dependency in your project:

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<dependency>
  <groupId>com.fasterxml.jackson.dataformat</groupId>
  <artifactId>jackson-dataformat-yaml</artifactId>
  <version>2.11.0</version>
</dependency>


Then, you can parse and validate a YAML file using the following code:

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import com.fasterxml.jackson.databind.ObjectMapper;

// Create a new ObjectMapper and configure it to read YAML files
ObjectMapper mapper = new ObjectMapper(new YAMLFactory());

// Read the YAML file and convert it to an object of the specified type
MyObject obj = mapper.readValue(new File("file.yaml"), MyObject.class);

// If the YAML file is invalid, the readValue method will throw a JsonMappingException


Member

by kendall , 4 months ago

@jeanie_reilly 

or a JsonParseException. You can handle the exception to validate the YAML file and take appropriate action.